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PHP is_resource() Function

❮ PHP Variable Handling Reference

Example

Check whether a variable is a resource or not:

<?php
$file = fopen("test.txt","r");

if (is_resource($file)) {
  echo "File is open";
} else {
  echo "Error open file";
}
?>
Run Example »

Definition and Usage

The is_resource() function checks whether a variable is a resource or not.

Note: The is_resource() function will return FALSE if the resource has been closed.

This function returns true (1) if the variable is a resource, otherwise it returns false/nothing.


Syntax

is_resource(variable);

Parameter Values

Parameter Description
variable Required. Specifies the variable to check

Technical Details

Return Value: TRUE if variable is a resource, FALSE otherwise
Return Type: Boolean
PHP Version: 4.0+

❮ PHP Variable Handling Reference